Equation of progressive wave is given by y=0.2cosπ(0.04t+0.02x−π6). The distance is expressed in cm and time in second. What will be the minimum distance between two particles having the phase difference of π2?
A
4cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
25cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
12.5cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C25cm Comparting with y=acos(ωt+kx−ϕ)
We get k=2πλ=0.02π ⇒λ=100cm Δϕ=π2. Hence, path difference between them Δx=λ2π×Δϕ =λ2π×π2 =λ4=1004=25cm