wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Equation of straight line midway between the lines x+2y1=0 and 2x+4y5=0 is

A
2x+4y3=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2x+4y7=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x+2y3=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
4x+8y7=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 4x+8y7=0
Line midway between ax+by+c1=0 and ax+by+c2=0 is ax+by+c1+c22=0
Hence, line midway between 2x+4y2=0 and 2x+4y5=0 is 2x+4y72=0
4x+8y7=0

Alternate Solution:
2x+4y2=0 and 2x+4y5=0
Let 2x+4y+k=0 be the required line.
Now
|k+2|20=|k+5|20|k+2|=|k+5|k=72
So the line will be
4x+8y7=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon