The correct options are
A Re(zz0)=1
C z¯¯¯¯¯z0+z0¯¯¯z=2r2
Let z=x+iy
Hence
|z|=r
Represents x2+y2=r2
Now z0=x0+iy0 is a point on x2+y2=r2.
Hence |z0|=r Since the center to the circle is at origin.
Using point contact form of tangent, we get the equation of tangent as
xx0+yy0=r2
This is nothing but the real part of
z.¯¯¯¯¯z0=r2=|z0|2
Re(zz0)=1
Now
Consider
z¯¯¯¯¯z0+z0¯¯¯z=2r2
Upon simplifying, we get
2xx0+2yy0=2r2
xx0+yy0=r2
Hence equation of tangent.