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Question

Equation of tangent drawn to circle |z|=r at the point A(z0) is

A
Re(zz0)=1
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B
z¯¯¯¯¯z0+z0¯¯¯z=2r2
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C
Im(zz0)=1
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D
Im(z0z)=1
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Solution

The correct options are
A Re(zz0)=1
C z¯¯¯¯¯z0+z0¯¯¯z=2r2
Let z=x+iy
Hence
|z|=r
Represents x2+y2=r2
Now z0=x0+iy0 is a point on x2+y2=r2.
Hence |z0|=r Since the center to the circle is at origin.
Using point contact form of tangent, we get the equation of tangent as
xx0+yy0=r2
This is nothing but the real part of
z.¯¯¯¯¯z0=r2=|z0|2
Re(zz0)=1
Now
Consider
z¯¯¯¯¯z0+z0¯¯¯z=2r2
Upon simplifying, we get
2xx0+2yy0=2r2
xx0+yy0=r2
Hence equation of tangent.

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