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Question

Equation of tangent for the parabola x2=4ay is

A
y=mxam2
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B
y=mx+am2
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C
y=mxam
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D
y=mx+am
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Solution

The correct option is A y=mxam2

let tangent is drawn at (h,k) and it has a slope m

x2=4ay2x=4adydxdydx=2x4a=x2a(dydx)(h,k)=h2a=mh=2amh2=4akk=4a2m24a=am2

Equation of tangent is

yk=m(xh)yam2=m(x2am)yam2=mx2am2y=mxam2

So option A is correct.


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