Question

Equation of tangent to the hyperbola $\frac{x^2}{a^2}-\frac{x^2}{b^2}=1$ at (asec$\theta$ , btan$\theta$) is $bxsec\theta -aytan\theta -ab=0$

• A. True
• B. false

Answer 1

The correct option is A True

True, We know equation of tangent to $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1at(x_1,y_1)$ is $T=S_1.$ Substituing (a sec$\theta$ , btan$\theta$) for $(x_1,y_1$) we get $bxsec\theta -aytan\theta -ab=0$