Equation of the chord of the hyperbola 25x2−16y2=400 which is bisected at the point (6, 2) is
A
6x−7y=418
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B
75x−16y=418
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C
25x−4y=400
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D
None of these
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Solution
The correct option is A75x−16y=418 Given hyperbola is 25x2−16y2=400 If (6, 2) is the midpoint of the chord, then equation of chord is T = S1 ⇒25(6x)−16(2y)=25(36)−16(4) ⇒75x−16y=450−32 ⇒75x−16y=418