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Question

Equation of the chord of the hyperbola 25x2−16y2=400 which is bisected at the point (6, 2) is

A
6x7y=418
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B
75x16y=418
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C
25x4y=400
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D
None of these
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Solution

The correct option is A 75x16y=418
Given hyperbola is 25x216y2=400
If (6, 2) is the midpoint of the chord, then equation of chord is T = S1
25(6x)16(2y)=25(36)16(4)
75x16y=45032
75x16y=418

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