wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

Equation of the chord of the hyperbola 25x2−16y2=400 which is bisected at the point (6, 2) is

A
6x7y=418
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
75x16y=418
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
25x4y=400
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 75x16y=418
Given hyperbola is 25x216y2=400
If (6, 2) is the midpoint of the chord, then equation of chord is T = S1
25(6x)16(2y)=25(36)16(4)
75x16y=45032
75x16y=418

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Lines and Points
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon