Equation of the circle passing through (4,3) and centre at the origin is _______ .
The formula for the equation of a circle is (x–h)2+(y–k)2=r2, where (h,k) represents the coordinates of the centre of the circle, and r represents the radius of the circle.
Given, centre = (0, 0) and (4, 3) is a point on the circle.
Then the radius 'r' of this circle is the distance between (4,3) and (0,0).
i.e., r2=(4−0)2+(3−0)2=25
Now, the equation of the circle is,
(x−0)2+(y−0)2=25
⟹x2+y2=25