Equation of the circle touching line $x + y - 4 = 0$ at the point $(2, 2)$ and passing through origin is -

x^{2} + y^{2} - 2 x - 2 y = 0

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x^{2} + y^{2} - 4 x - 4 y = 0

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x^{2} + y^{2} - 2 x + 2 y = 0

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x^{2} + y^{2} = 8

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Solution

The correct option is A $x^{2} + y^{2} - 2 x - 2 y = 0$

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Similar questions

Find the equation of circle which touches $2 x - y + 3 = 0$ and pass through the points of intersection of the line $x + 2 y - 1 = 0$ and the circle $x^{2} + y^{2} - 2 x + 1 = 0$

Q. The equation of the circle passing through points of intersection of the circle

x^{2} + y^{2} - 2 x - 4 y + 4 = 0

and the line

x + 2 y = 4

and touches the line

x + 2 y = 0

, is

The equation of the circle through the points of intersection of $x^{2} + y^{2} - 1 = 0, x^{2} + y^{2} - 2 x - 4 y + 1 = 0$ and touching the line x + 2y = 0, is