Equation of the circle with centre (1,2) and passing through (2,1) is

x²+y²-6x+10y+18=0

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x²+y²+6x-10y+18=0

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x²+y²-6x+10y+25=0

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x²+y²-2x-4y+3=0

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Solution

The correct option is D
x²+y²-2x-4y+3=0

C = (1,2)
P(2,1)
r = CP = $\sqrt{1 + 1}$ = $\sqrt{2}$
$(x - 1)^{2} + (y - 2)^{2}$ = 2 $\Rightarrow x^{2} + y^{2} - 2 x - 4 y + 3 = 0$

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