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Question

Equation of the curve passing through the point (4,3) and having slope =y/2 at a point (x,y) on it is

A
log(y3)=x22
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B
log(y3)=x2+2
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C
y=3ex2
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D
y2=x+5
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Solution

The correct option is A log(y3)=x22
dydx=y2 (given)
dydx=dx2
logy=12x+c
since this curve passes through (4,3)
log3=12×4+c
log3=2+c
c=log32
Hence Equation of the curve is
logy=12x+log32
logylog3=x22
log(y3)=x22

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