Equation of the curve whose subnormal is constant is given by:
A
y2=2kx+c
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B
y2=2kx2+c
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C
y2−x2=2kx+c
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D
x2=2ky+c
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Solution
The correct option is Dy2=2kx+c Angle at N=π−[π2+π−ψ]=ψ−π2 Sub normal,NK=ycot(ψ−π2) NK=−ycot(π/2−ψ) NK=−ytanψ Given,NK=Constant ytanψ=−k Slope,tan(π−ψ)=dydx tanψ=−dydx −ydydx=−k ydy=∫kdx On intergrating both sides ∫(ydy)=∫(kdx) ⇒y22=kx+C ⇒y2=2kx+C is the required equation.