CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Equation of the ellipse with focus (3,2), eccentricity 14 and directrix 2xy+3=0 is :

A
76x2+79y24xy492x326y1031=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
76x2+79y2+4xy492x+326y+1031=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
44x2+36xy+71y2125x274y+659=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
44x2+36xy+71y2135x47xy+859=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 76x2+79y2+4xy492x+326y+1031=0
Focus S(3,2)
e=14
Equation of directrix is 2xy+3=0
Let P(x,y) be a point on the ellipse.
Since, for an ellipse
PS2=e2PM2
(x3)2+(y+2)2=116(2xy+3)25
76x2+79y2+4xy492x+326y+1031=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ellipse and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon