Question

Equation of the ellipse with vertices (-4,3), (8,3) and e=$\frac{5}{6}$ is

• A. $\frac{(x-2{)}^2}{36}+\frac{(y-3{)}^2}{11}$ = 1
• B. $\frac{(x{)}^2}{36}+\frac{(y{)}^2}{11}$ = 1
• C. $\frac{(x-2{)}^2}{11}+\frac{(y-1{)}^2}{36}$ = 1
• D. $\frac{(x-2{)}^2}{9}+\frac{(y-3{)}^2}{16}$ = 1

Answer 1

The correct option is A

$\frac{(x-2{)}^2}{36}+\frac{(y-3{)}^2}{11}$ = 1

A(-4,3),B(8,3), its centre C=(2,3), e = $\frac{5}{6}$

2a = 12 $\Rightarrow$ a = 6, $b^2$ = 36(1-$\frac{25}{36})$ = 11

$\frac{(x-2{)}^2}{36}+\frac{(y-3{)}^2}{11}$ = 1