Equation of the hyperbola with foci (0,± 5) and e = 53 is
yz9−yz16=1
xz16−yz9=1
xz12−yz13=1
Foci = ( 0 , ±5 ) = ( 0 , ± be)
b53 = 5 ⇒ b = 3
a2=9(259−1) = 16
x216−y29=−1
The value of 52xyz(xy+yz+xz+y2)(z+x)×104xy(xy+xz+yz+y2) is:
If the line y=mx+1 touches the hyperbola xz9−yz2 = 1 then m =
Question 29 Factorise the following: