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Question

Equation of the hyperbola with foci (0,± 5) and e = 53 is


A

yz9yz16=1

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B

xz16yz9=1

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C

xz16yz9=1

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D

xz12yz13=1

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Solution

The correct option is B

xz16yz9=1


Foci = ( 0 , ±5 ) = ( 0 , ± be)

b53 = 5 b = 3

a2=9(2591) = 16

x216y29=1


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