wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Equation of the hyperbola with length of the latusrectum 4 and e = 3 is


A

2x216y2=1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

3x215y2=1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

16x22y2=1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

8x2y2=1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

16x22y2=1


2b2a=4 e = 3

b2=2a

a2(e21)=2a

a(8) = 2 a = 14 , b2=12

x2116y212=1

16 x22y2=1


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hyperbola and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon