Equation of the image of the pair of rays y = | x | by the line x = 1 is
A
|y|=x + 2
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B
|y| + 2 = x
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C
y = |x - 2|
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D
y=x+2 and y=x-2
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Solution
The correct option is C y = |x - 2| Solution : y = |x| gives
y = x ...(1)
and y = -x ...(2)
Image of line (1) passes through (2, 0) and perpendicular to (1)
i.e. y = 2 - x ..(3)
Similarly image of live (2) also passes (2, 0) and perpendicular to (2) i.e. y = x - 2 ...(4)