Equation of the line on which the length of the perpendicular from origin is 5 and the angle which this perpendicular makes with the x axis is $60^{\circ}$ .

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Solution

The correct option is D

Clearly the data given in the question is based on 'Normal form'. So consider Normal form of the straight line i.e. xcos $α$ +ysin $α$ =p

Here α= $60^{\circ}$ and p=5

$∴$ Required line is $x + \sqrt{3} y = 10$

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Equation of the line on which the length of the perpendicular from origin is 5 and the angle which this perpendicular makes with the x axis is 60∘.

The correct option is D Clearly the data given in the question is based on 'Normal form'. So consider Normal form of the straight line i.e. xcosα+ysinα=p Here α=60∘ and p=5 ∴ Required line is x+√3y=10

Equation of the line on which the length of the perpendicular from origin is 5 and the angle which this perpendicular makes with the x axis is $60^{\circ}$ .

The correct option is D

Clearly the data given in the question is based on 'Normal form'. So consider Normal form of the straight line i.e. xcos $α$ +ysin $α$ =p

Here α= $60^{\circ}$ and p=5

$∴$ Required line is $x + \sqrt{3} y = 10$