Equation of the line passing through (–1, 1) and perpendicular to the line 2x + 3y + 4 = 0, is

3x - 2y - 5 = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3x - 2y - 5 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3x - 2y = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3x+ 2y - 5 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 3x - 2y - 5 = 0
The given line is 2x + 3y + 4 = 0
y = $\frac{- 2}{3}$ x - $\frac{4}{3}$

slope of the line is $\frac{- 2}{3}$
slope of perpendicular is $\frac{3}{2}$

The line passes through (-1, 1)
Thus the equation of the line using point-slope form is.
y - 1 = $\frac{3}{2}$ (x + 1)
2y- 2 = 3x + 3
3x - 2y = 5

Suggest Corrections

Similar questions

The equation of a straight line passing through the origin and perpendicular to the straight line 2x + 3y - 7 = 0 is ______.

2 x + y = 1

3 x + 2 y = 5

Find the equation of the line parallel to the line $3 x + 2 y = 8$ and passing through the point $(0, 1)$ .

x + 2 y = 5

3 x + 7 y = 17

3 x + 4 y = 10

x - y - 5 = 0

{(\frac{15}{A B})}^{2} + {(\frac{10}{A C})}^{2} = {(\frac{6}{A D})}^{2}

Join BYJU'S Learning Program