Question

Equation of the line passing through (–1, 1) and perpendicular to the line 2x + 3y + 4 = 0, is

• A. 3x - 2y - 5 = 0
• B. 3x - 2y - 5 = 0
• C. 3x - 2y = 0
• D. 3x+ 2y - 5 = 0

Answer 1

The correct option is A 3x - 2y - 5 = 0

The given line is 2x + 3y + 4 = 0
y = $\frac{-2}{3}$x - $\frac{4}{3}$

slope of the line is $\frac{-2}{3}$
slope of perpendicular is $\frac{3}{2}$

The line passes through (-1, 1)
Thus the equation of the line using point-slope form is.
y - 1 = $\frac{3}{2}$ (x + 1)
2y- 2 = 3x + 3
3x - 2y = 5