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Question

Equation of the line passing through (1, 2) and parallel to the line

y=3x1 is


A
y + 2 = x + 1
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B
y + 2 = 3(x + 1)
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C
y – 2 = 3(x – 1)
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D
y – 2 = x – 1
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Solution

The correct option is C y – 2 = 3(x – 1)

We are given the point, all we have to do is to find the slope.

From the equation y=3x1

the slope of the line parallel to this line will be 3.

Therefore the required equation which passes through (1, 2) and with gradient as 3, is

(y2)=3(x1)


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