Equation of the line passing through (1, 2) and parallel to the line $y = 3 x - 1$ is .

3x - y + 1 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3x - y - 1 = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3x - y = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3x +y + 1 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
B 3x - y - 1 = 0
C 3x - y = 0
We are given the point, all we have to do is to find the slope.

From the equation $y = 3 x - 1$

the slope of the line parallel to this line will be 3.

Therefore the required equation which passes through (1, 2) and with gradient as 3, is
y – 2 = 3 (x – 1)
y - 2 = 3x - 3
3x - y + 1 = 0

Suggest Corrections

Similar questions

Equation of the line passing through (1, 2) and parallel to the line $y = 3 x - 1$ is .

Equation of the line passing through $(1, 2)$ and parallel to the line $y = 3 x - 1$ is

Find out which of the following equations have x=1, y=2 as solution.
x + 2y = 5
2y - 3x + 3 = 0
3x + 4y - 8 = 0 [4 MARKS]

a

2 x + y - 1 = 0 a x + 3 y - 3 = 0 3 x + 2 y - 2 = 0

Join BYJU'S Learning Program