Equation of the line passing through (1, 2) and parallel to the line y=3x–1 is
We are given the point, all we have to do is to find the slope.
From the equation y=3x–1
the slope of the line parallel to this line will be 3.
Therefore the required equation which passes through (1, 2) and with gradient as 3, is
y – 2 = 3 (x – 1)
y - 2 = 3x - 3
3x - y + 1 = 0