Equation of the line passing through the point (1,2) and perpendicular to the line y=3x−1 is
A
x+3y−7=0
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B
x+3y+7=0
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C
x+3y=0
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D
x−3y=0
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Solution
The correct option is Ax+3y−7=0 Slope of the line y=3x−1 is 3. Slope of the line perpendicular to the given line will be −13 Equation of the line passing htrough (1,2) and having slope −13 is :x+3y−7=0