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Question

Equation of the parabola whose vertex is (3,2), axis is horizontal and which passes through the point (1,2) is

A
y2+4y+4x8=0
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B
y2+4y4x+8=0
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C
y2+4y4x8=0
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D
none of these
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Solution

The correct option is C y2+4y4x8=0
Since the axis is horizontal and vertex is (3,2) and passes through (1,2).
the equation of the parabola must be of the form
(y+2)2=4a(x+3)
It passes through (1,2),
16=16aa=1

Hence, the equation of the required parabola is
(y+2)2=4(x+3)
or y2+4y4x8=0

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