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Question

Equation of the plane with intercepts 2, 3, 4 on the x, y and z axis respectively is

A
2x+3y+4z=1
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B
2x+3y+4z=12
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C
6x+4y+3z=1
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D
6x+4y+3z=12
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Solution

The correct option is D 6x+4y+3z=12
The equation of plane with intercepts a,b,c is given as xa+yb+zc=1

The equation of plane with intercepts 2,3,4 is x2+y3+z4=1

12x+8y+6z=24

6x+4y+3z=12

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