Equation of the straight line passing through point of intersection of the line xa+yb=1 and xb+ya=1 and is making an angle π4 with the line 2x−2y+3=0 is
A
(a+b)x=ab
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B
(a+b)x+ab=0
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C
(a+b)y=ab
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D
aby=a+b
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Solution
The correct option is C(a+b)y=ab Point of intersection of xa+yb=1 and xb+ya=1 is (aba+b,aba+b)
Given line 2x−2y+3=0 makes an angle π4 with the positive direction of x-axis ∴ Required line which makes an angle π4 with this line will be parallel to x-axis or y-axis. i.ex=aba+bory=aba+b