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Question

Equation of the straight line passing through the point of intersection of the lines 3x+4y=7,xy+2=0 and having slope 3 is


A

21x7y+16=0

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B

9x3y+14=0

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C

21x7y+12=0

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D

9x3y+5=0

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Solution

The correct option is A

21x7y+16=0


On solving the two equations, we get the point of intersection as (17, 137)

Slope of the required equation m=3

Therefore, using point-slope form

(yy1)=m(xx1)

y137=3(x17)

7y13=21x+3

21x7y+16=0


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