Equation of the tangent to the conic $x^{2} - y^{2}$ - 8x+2y+11=0 at (2,1) is

x+2=0

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2x+y-5=0

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x+y-3=0

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x-2=0

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Solution

The correct option is D
x-2=0

$x^{2} - y^{2}$ - 8x+2y+11=0 (2, 1)

$\Rightarrow$ 2x-y-4(x+2) +1(y+1) +11=0

$\Rightarrow$ -2x+4=0 x-2=0

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