y2=6xa=64=32 L=(32,3) Eqn of tgt is (y−3)=(x−32) ⇒x−y+32=0⇒2x−2y+3=0
Equation of the tangent to y2=6x at the positive end of the latusrectum is
Equation of the circle on the latusrectum of y2=8x as ends of diameter is