Question

Equation of the transverse axis of the hyperbola $\frac{(y-2{)}^2}{9}-\frac{(x+3{)}^2}{16}=1$ is

• A. $x+3=0$
• B. $x-5=0$
• C. $x-7=0$
• D. $x-9=0$

Answer 1

Answer: (A)

$x+3=0$

Given hyperbola is, $\frac{(y-2{)}^2}{9}-\frac{(x+3{)}^2}{16}=1$
clearly its transverse axis is $x+3=0$