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Question

# Equation of trajectory of a projectile is given by y=−x2+10x where x and y are in meters and x is along horizontal and y is vertically upward and particle is projected from origin. Then which of the following options is/are correct. (g=10m/s2).

A
Initial velocity of particle is 505 m/s
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B
Horizontal range is 10 m
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C
Maximum height is 25 m
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D
Angle of projection with horizontal is tan1(5)
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Solution

## The correct option is C Initial velocity of particle is √505 m/sy=−x2+10xComparing with Standard equation of trajectory y=tanθx−gx22u2cos2θWe get tanθ=10 and g2u2cos2θ=1cosθ=1√101u=√505m/s

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