Equation(s) of the line perpendicular to x=y and at a distance of 1 unit from origin is/are
A
x+y+√2=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3x+4y+5=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x+y−√2=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
3x+4y−5=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct options are Ax+y+√2=0 Cx+y−√2=0 Equation of the line perpendicular to x=y will be of form x+y+k=0 Distance from origin to the required line is 1 unit |k|√2=1⇒k=±√2 Hence required line equation's are x+y±√2=0