Equation to the straight line cutting off an intercept 2 from negative direction of the axis of y and inclined at 300 to the positive direction to the axis of x is :-
A
y+x−√3=0
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B
y−x+2=0
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C
y−√3x−2=0
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D
√3y−x+2√3=0
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Solution
The correct option is D√3y−x+2√3=0 m=tan30o=1√3 m=tan30o=1√3 c=−2 y=1√3x−2