Question

Equations of diagonals of the square formed by the lines x = 0, y = 0, x = 1 and y = 1 are

(a) y = x, y = x + 1

(b) y = x, x + y = 2

(c) $2y=x,x+y=\frac{1}{3}$

(d) y = 2x, y = 2x + 1

Answer 1

Check Answer
Since square is formed by x = 0, y = 0, x = 1 and y = 1

Clearly coordinate of A = (0, 1) B = (1, 1) C = (1, 0) and D = (0, 0)
∴ Equation of diagonal AC is given by

$$\begin{gathered} \frac{y-0}{x-1}=\frac{0-1}{1-0} \\ \mathrm{i}.\mathrm{e}.y=-\left(x-1\right) \\ \mathrm{i}.\mathrm{e}.x+y-1=0 \end{gathered}$$
And equation of diagonal BD is
$$\begin{gathered} \frac{y-1}{x-1}=\frac{0-1}{0-1} \\ \mathrm{i}.\mathrm{e}.y-1=x-1 \\ \mathrm{i}.\mathrm{e}.y=x \end{gathered}$$