Equations of preparation of alcohol from sugar are given:
$C_{12} H_{22} O_{11} + H_{2} O I n v e r t a s e - ----- \to C_{6} H_{12} O_{6} A + C_{6} H_{12} O_{6} B$
$C_{6} H_{12} O_{6} z y m a s e - --- \to 2 C_{2} H_{5} O H + 2 {C O}_{2}$
(a) Write the names of the Compounds $A$ and $B$ .
(b) The alcohol obtained here is known as .............
(c) How can this alcohol be converted into reflected spirit?
(d) How can power alcohol be prepared?

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Solution

(a) Glucose and fructose
(b) Wash
(c) By fractional distillation
(d) Power alcohol is prepared by mixing absolute alcohol with petrol.

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Similar questions

C_{12} H_{22} O_{11} + H_{2} O H^{+} - - \to C_{6} H_{12} O_{6} + C_{6} H_{12} O_{6}

C_{6} H_{12} O_{6} + 2 A D P + 2 P i ⟶ 2 C_{2} H_{5} O H + 2 A T P + 2 C O_{2} ↑

C_{12} H_{22} O_{11} + H_{2} O \to C_{6} H_{12} O_{6} + C_{6} H_{12} O_{6}

2.12 \times 10^{- 4} L {m o l}^{- 1} {s e c}^{- 1}

27^{o} C

1.07 \times 10^{5} J {m o l}^{- 1}

37^{o} C

{Δ H}_{f}^{o}

C_{6} H_{12} O_{6} (s)

Δ H_{c o m b .}

C_{6} H_{12} O_{6} (s) = - 2816 k J {m o l}^{- 1}

{Δ H}_{f}^{o}

{C O}_{2} (g) = - 393.5 J {m o l}^{- 1}

{Δ H}_{f (H_{2} O)}^{o} = - 285.9 k J {m o l}^{- 1}

6 C O_{2} + 6 H_{2} O ⟶ C_{6} H_{12} O_{6} + 6 O_{2}

6 C O_{2} + 6 H_{2} O ⟶ C_{6} H_{12} O_{6} + 6 O_{2}

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