Equations of tangents to the hyperbola 4x2−3y2=24 which makes an angle 30o with y−axis are
Given
that:
4x2−3y2=24
On dividing by 24, we get
x2(√6)2−y2(2√2)2=1
a=√6,b=2√2
Now,
Equation of tangent
y=mx±√a2m2−b2
As the line makes an angle of 30∘ from y−axis,
∴m=tan120∘=−cot30∘=−√3 (See in the figure)
On substituting the values of a,b and m, we get
y=−√3x±√6×3−8
y=−√3x±√10
y+√3x=±√10
Hence, this is the answer.