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Question

Equations to the sides of a triangle are x3y=0, 4x+3y=5 and 3x+y=0. The line 3x4y=0 passes through the


A

incentre

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B

circumcentre

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C

centroid

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D

orthocentre of the triangle

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Solution

The correct option is D

orthocentre of the triangle


Sides x3y=0 and 3x+y=0 of the triangle are perpendicular to each other. Hence, the triangle is right angled at origin, which is the point of intersection of these sides. This implies that the origin is the orthocentre of the triangle and the line 3x4y=0 passes which passes through the origin, passes through the orthocentre of the triangle.


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