Question

Equilibrium constant for two complexes are:
$A:K_4\left[Fe{\left(CN\right)}_6\right];2.6\times {10}^{37}$ (for dissociation)
$B:K_3\left[Fe{\left(CN\right)}_6\right];1.9\times {10}^{17}$ (for dissociation)

• A. $A$ and $B$ are equally stable
• B. $A$ is more stable than $B$
• C. $B$ is more stable than $A$
• D. The predictable stability

Answer 1

The correct option is C $B$ is more stable than $A$

Equilibrium constant for two complexes are:
$A:K_4\left[Fe{\left(CN\right)}_6\right];2.6\times {10}^{37}$ (for dissociation)
$B:K_3\left[Fe{\left(CN\right)}_6\right];1.9\times {10}^{17}$ (for dissociation)

$B$ is more stable than $A$ as $B$ has lower value of equilibrium constant (for dissociation) than that for $A$. Lower value of equilibrium constant means greater stability.
$Stability\propto \frac{1}{Equi.constantfordissociation}$