Question

Equilibrium constant $K_c$ for the reaction at 300 K is:

• A. $5.572\times {10}^5$ at 300 K
• B. $3.672\times {10}^5$ at 300 K
• C. $7.372\times {10}^5$ at 300 K
• D. None of these

Answer 1

Answer: (A)

$5.572\times {10}^5$ at 300 K

Given, $\Delta H=E_f-E_b=-33kJ$
$K_f=A{e}^{-E_f/RT}$
$K_b=A{r}^{-E_b/RT}$
$\therefore K_c=\frac{K_f}{K_b}=e^{[E_b-E_f]/RT}=e^{\frac{33\times {10}^3}{8.314\times 300}}$
$=5.572\times {10}^5$ at 300 K