Question

Equilibrium constant of some reactions are given as under:

$\left(a\right)x\rightleftharpoons yK={10}^{-1}$

$\left(b\right)y\rightleftharpoons zK={2\times 10}^{-2}$

$\left(c\right)P\rightleftharpoons QK={3\times 10}^{-4}$

$\left(d\right)R\rightleftharpoons SK={2\times 10}^{-3}$

Initial concentration of the reactants for each reaction was taken to be equal:
Review the above reaction and indicate the reaction in which the reactants and products respectively were of highest concentration:

• A. d, c
• B. c, a
• C. a, d
• D. b, c

Answer 1

The correct option is B c, a

Equilibrium constant $K$ is equal to

$K=\frac{\left[P\right]}{\left[R\right]}=\frac{\left[ConcentrationofProduct\right]}{\left[ConcentrationofReactant\right]}$

If the reaction has more amount of product it means the value of $K$ is more and $K$ will be small if the concentration of reactant increases.

In equation (a) $K$ is maximum so it has highest product concentration and equation (c) has smallest $K$ so it has more amount of reactants.

Hence, option B is correct