1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Equilibrium constants for the following reaction at 1200 K are given.2H2O(g)⇋2H2(g)+O2(g);K1=6.4×10−82CO2(g)⇋2CO(g)+O2(g);K2=1.6×10−6The equilibrium constant for the reactionH2(g)+CO2(g)⇋CO(g)+H2O(g) at 1200 K will be:

A
0.05
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
20
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D 512×[2H2O⇋2H2+O2;K1]H2O⇋H2+12O2;K′=√K1H2+12O2⇋H2O;K"=1√K1 ....... (1)12×[2CO2⇋2CO+O2;K2]CO2⇋CO+12O2;√K2=K" ....... (2)From equations (1) and (2).H2+12O2⇋H2O;K"=1√K1CO2⇋CO+12O2;K"=√K2--------------------------------------------------------------------------------H2+CO2⇋H2O+COK=K"×K"=1√K1×√K2=√K2K1=√1.6×10−66.4×10−8=√14×102=√25=5Hence, the correct option is D

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Equilibrium Constants
CHEMISTRY
Watch in App
Join BYJU'S Learning Program