Question

Equilibrium constants for the reaction,
$2NO\left(g\right)+C{l}_2\left(g\right)\rightleftharpoons 2NOCl\left(g\right)$ is correctly given by the expression:

• A. $K=\frac{\left[2NOCl\right]}{\left[2NO\right]\left[C{l}_2\right]}$
• B. $K=\frac{[NOCl{]}^2}{\left[NO{]}^2\right[C{l}_2]}$
• C. $K=\frac{[NOCl{]}^2}{\left[NO{]}^2\right[C{l}_2{]}^2}$
• D. $K=\frac{[NOCl{]}^2}{[NO{]}^2+[C{l}_2]}$

Answer 1

The correct option is B $K=\frac{[NOCl{]}^2}{\left[NO{]}^2\right[C{l}_2]}$

By law of chemical equilibrium, $K_c$ is the ratio of active masses of product & active masses of reactants.

Thus, $K=\frac{[NOCl{]}^2}{\left[NO{]}^2\right[C{l}_2]}$