Question

Equilibrium position of which of the following reactions is not affected by change in pressure?

• A. $I_{2\left(s\right)}+5F_{2\left(g\right)}\to 2I{F}_{5_{(}g)}$
• B. $Fe{O}_{\left(s\right)}+C{O}_{\left(g\right)}\to F{e}_{\left(s\right)}+C{O}_{\left(g\right)}$
• C. $2Cu(N{O}_3{)}_{2_{(}s)}\to 2Cu{O}_{\left(s\right)}+4N{O}_{2_{(}g)}+O_{2_{(}g)}$
• D. $N{O}_2{O}_{4_{(}g)}\to 2N{O}_{2_{(}g)}$

Answer 1

The correct option is B $Fe{O}_{\left(s\right)}+C{O}_{\left(g\right)}\to F{e}_{\left(s\right)}+C{O}_{\left(g\right)}$

Change in pressure affects the equilibrium position of the reaction only when there is a change in the number of molecules or moles.

In the reaction given in (B), there is no change in number of molecules, (no. of molecules of reactants = no. of molecules of products = 2) , therefore change in pressure doesnot affect the equilibrium position.

In all other reactions, there is a change in the number of molecules and hence, change in pressure affects the equilibrium position of the reaction.