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Question

Equivalent conductance of 1M CH3COOH is 10 ohm−1 cm2 equi−1 and that at infinite dilution is 200 ohm−1 cm2 equiv−1. Hence the % ionization of CH3COOH is:

A
5%
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B
2%
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C
4%
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D
1%
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Solution

The correct option is A 5%
Degree of ionization can be defined as a ratio of equivalent conductance at concentration c to the equivalent conductance at infinite dilution. It can be given as follows:
α=λcλ
λc is given as 10 ohm1cm2equi1
λ is given as 200 ohm1cm2equi1
So, α=10200=0.05
% ionization = α×100=0.05×100=5 %

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