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Question

Equivalent conductance of saturated solution of BaSO4 is 200 ohm1 cm2 eqv1 and specific conductance is 4×105 ohm1 cm1. Ksp of BaSO4 x ×10y M2 in scientific notation. The value of (x + y) will be:

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Solution

Given : Equivalent conductance = 200 ohm1 cm2 eqv1
Specific conductance (κ)=4×105 ohm1 cm1
we know,
equivalent conductance=κ×1000Normality

Normality=4×105×1000200=2×104
(n-factor of BaSO4=2)
Molarity =104
Now, BaSO4Ba2++SO24
Ksp=[Ba2+][SO24]=[C].[C]
=104×104=1×108M2
x=1, y=8, So x+y=9

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