Question

Equivalent conductivity of acetic acid at infinite dilution is $390.7$mho $c{m}^2$gm. $equi{v}^2$ and for $0.1$ M acetic acid is $5.2$mho $c{m}^2$ gm.$equi{v}^2$. Calculate degree of dissociation, $H^{+}$ ion concentration and dissociation constant of the acid.

Answer 1

$K=\frac{{\alpha }^{2}C}{1-\alpha }=\frac{{0.0133}^2\times 0.1}{(1-0.133)}=2.38\times {10}^{-5}M$
Solution:
$\alpha =1.33$
$H^{+}=0.00133$M
$K=2.38\times {10}^{-5}$M.