Equivalent conductivity -e q

The correct option is D k × 1000/Nohm^ 1 cm^rEq^ 1N normalityEquivalent conductivity (∧_eq)=k × V As equivalent conductivity is conductivity of 1 gm equivalen ...

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Standard X

Chemistry

Oxidation and Reduction

Equivalent co...

Question

Equivalent conductivity $\land_{e q}$

\frac{k \times 1000}{m} o h m^{- 1} c m^{r} E q^{- 1} m - m o l a l i t y

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\frac{k \times 1000}{M} o h m^{- 1} c m^{r} E q^{M} - m o l a r i t y

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\frac{k \times 1000}{N} o h m^{- 1} c m^{r} E q^{- 1} N - n o r m a l i t y

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Solution

The correct option is C $\frac{k \times 1000}{N} o h m^{- 1} c m^{r} E q^{- 1} N - n o r m a l i t y$
Equivalent conductivity $(\land_{e q}) = k \times V$
As equivalent conductivity is conductivity of 1 gm equivalent.
$∴ \land_{e q} = k \times V$
$= k \times \frac{1000}{N}$ where N is normality.

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Equivalent conductivity ∧eq

The correct option is C k×1000Nohm−1cmrEq−1N−normalityEquivalent conductivity (∧eq)=k×V As equivalent conductivity is conductivity of 1 gm equivalent. ∴∧eq=k×V =k×1000N where N is normality.

Equivalent conductivity $\land_{e q}$

The correct option is C $\frac{k \times 1000}{N} o h m^{- 1} c m^{r} E q^{- 1} N - n o r m a l i t y$
Equivalent conductivity $(\land_{e q}) = k \times V$
As equivalent conductivity is conductivity of 1 gm equivalent.
$∴ \land_{e q} = k \times V$
$= k \times \frac{1000}{N}$ where N is normality.