Equivalent mass of bivalent metal is $32.7$ . Molar mass of its chloride is :

68.2 g {m o l}^{- 1}

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103.7 g {m o l}^{- 1}

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136.4 g {m o l}^{- 1}

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166.3 g {m o l}^{- 1}

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Solution

The correct option is B $136.4 g {m o l}^{- 1}$
Atomic mass of metal is $32.7 \times 2 = 65$ g
So, molar mass of metal chloride $M {C l}_{2} = 2 \times 32.7 + 71 = 136.4 g {m o l}^{- 1}$

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