The correct option is
B
42.6
The two half-reactions are:
Oxidation: 6OH− + ½ Cl2 → 2ClO−3 + 5e− + 3H2O
Reduction: 52Cl2 + 5e− → 5Cl−
3 moles of Cl2 and 5 moles of electrons are involved in the redox reaction
Molar mass of Cl2 = 71g/mol
Equivalentmassofoxidisingagent(or)reducingagent=no.ofmolesofoxidisingorreducingagent×Molarmassno.ofelectronstakingpartinredoxreaction
Therefore, the equivalent mass of Cl2 in the reaction = 3×715=42.6gmol