Equivalent mass of chlorine molecule in the equation 3 Cl 2-6 NaOH - 5 NaCl - NaClO 3-3 H 2 OA- 59-1B- 42-6C- 71D- 35-5

The correct option is B 42.6It is a disproportionation reaction of chlorine Equivalent mass of chlorine molecule =M/2+M/10=3M/5 ...

You visited us 7 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Oxyacids of Phosphorus

Equivalent ma...

Question

Equivalent mass of chlorine molecule in the equation
$3 C l_{2} + 6 N a O H \to 5 N a C l + N a C l O_{3} + 3 H_{2} O$

42.6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

35.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

59.1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is
B
42.6
The two half-reactions are:
Oxidation: 6 $O H^{-}$ + ½ $C l_{2}$ → 2 $C l O_{3}^{-}$ + 5 $e^{-}$ + 3 $H_{2} O$
Reduction: $\frac{5}{2} C l_{2}$ + $5 e^{-}$ → 5 $C l^{-}$
3 moles of $C l_{2}$ and 5 moles of electrons are involved in the redox reaction
Molar mass of $C l_{2}$ = 71g/mol
$E q u i v a l e n t m a s s o f o x i d i s i n g a g e n t (o r) r e d u c i n g a g e n t = \frac{n o . o f m o l e s o f o x i d i s i n g o r r e d u c i n g a g e n t \times M o l a r m a s s}{n o . o f e l e c t r o n s t a k i n g p a r t i n r e d o x r e a c t i o n}$
Therefore, the equivalent mass of $C l_{2}$ in the reaction = $\frac{3 \times 71}{5} = \frac{42.6 g}{m o l}$

Suggest Corrections

Similar questions

Q. The equivalent weight of chlorine molecule in the given equation is

3 C l_{2} + 6 N a O H \to 5 N a C l + N a C l O_{3} + 3 H_{2} O

Q. The equivalent weight of chlorine molecule in the equation:

3 C l_{2} + 6 N a O H \to 5 N a C l + N a C l O_{3} + 3 H_{2} O

Q. Equivalent weight of chlorine molecule in the equation is:

3 C l_{2} + 6 N a O H ⟶ 5 N a C l + N a C l O_{3} + 3 H_{2} O

Q. The equivalent weight of chlorine molecule in the given equation is

3 C l_{2} + 6 N a O H \to 5 N a C l + N a C l O_{3} + 3 H_{2} O

The weight of chlorine gas undergoing oxidation when excess of chlorine is sent into hot concentrated caustic soda solution containing 24 grams of solute in it
$3 C l_{2} + 6 N a O H \to 5 N a C l + N a C l O_{3} + 3 H_{2} O$

Join BYJU'S Learning Program

Equivalent mass of chlorine molecule in the equation 3Cl2+6NaOH→5NaCl+NaClO3+3H2O

Equivalent mass of chlorine molecule in the equation
$3 C l_{2} + 6 N a O H \to 5 N a C l + N a C l O_{3} + 3 H_{2} O$