Equivalent mass of chlorine molecule in the equation 3 Cl 2-6 NaOH - 5 NaCl - NaClO 3-3 H 2 OA- 59-1B- 42-6C- 71D- 35-5

The correct option is B 42.6It is a disproportionation reaction of chlorine Equivalent mass of chlorine molecule =M/2+M/10=3M/5 ...

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Standard XII

Chemistry

Oxyacids of Phosphorus

Equivalent ma...

Question

Equivalent mass of chlorine molecule in the equation
$3 C l_{2} + 6 N a O H \to 5 N a C l + N a C l O_{3} + 3 H_{2} O$

42.6

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35.5

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59.1

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Solution

The correct option is
B
42.6
The two half-reactions are:
Oxidation: 6 $O H^{-}$ + ½ $C l_{2}$ → 2 $C l O_{3}^{-}$ + 5 $e^{-}$ + 3 $H_{2} O$
Reduction: $\frac{5}{2} C l_{2}$ + $5 e^{-}$ → 5 $C l^{-}$
3 moles of $C l_{2}$ and 5 moles of electrons are involved in the redox reaction
Molar mass of $C l_{2}$ = 71g/mol
$E q u i v a l e n t m a s s o f o x i d i s i n g a g e n t (o r) r e d u c i n g a g e n t = \frac{n o . o f m o l e s o f o x i d i s i n g o r r e d u c i n g a g e n t \times M o l a r m a s s}{n o . o f e l e c t r o n s t a k i n g p a r t i n r e d o x r e a c t i o n}$
Therefore, the equivalent mass of $C l_{2}$ in the reaction = $\frac{3 \times 71}{5} = \frac{42.6 g}{m o l}$

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Equivalent mass of chlorine molecule in the equation 3Cl2+6NaOH→5NaCl+NaClO3+3H2O

Equivalent mass of chlorine molecule in the equation
$3 C l_{2} + 6 N a O H \to 5 N a C l + N a C l O_{3} + 3 H_{2} O$